20x^2=980

Solution for 20x^2=980 equation:

20x^2=980

We move all terms to the left:

20x^2-(980)=0

a = 20; b = 0; c = -980;
Δ = b2-4ac
Δ = 02-4·20·(-980)
Δ = 78400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{78400}=280$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-280}{2*20}=\frac{-280}{40}
=-7
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+280}{2*20}=\frac{280}{40}
=7
$